Electric Flux

The SI unit of electrical flux is:

If $\underset{S}{\oint } \overrightarrow{E}·d\overrightarrow{S}=0$ over a surface, then:

Given the electric field in the region $x$ is $2E$, find the net electric flux through the cube and the charge enclosed by it. 

A uniform electric field is applied parallel to the base of a regular circular cone pyramid as shown. The flux through the curved surface is

Coordinates of a square are given as $(1, 1, 0) \mathrm{m},$ $(1,1,0) \mathrm{m}$ $(-1,-1, 0) \mathrm{m}$, $(1,-1,0) \mathrm{m}$. If electric field is $10 \mathrm{V} {\mathrm{m}}^{-1}$ along z-axis, electric flux through square is 

The image below shows two examples of electric field lines.

Which of the following statements is true?

 A square sheet of $5.0 \mathrm{cm}$is placed in an electric field $E=(1.6 \times {10}^4 \mathrm{N} {\mathrm{C}}^{-1} )\hat{\mathrm{i}}$ such that the normal unit vector for the sheet is $\left(\frac{\sqrt{3}}{2}\right)\hat{\mathrm{i}}+\left(\frac{1}{2}\right) \hat{\mathrm{j}}$ The electric flux through the sheet is:

Consider a cube of side $a=0.1 \mathrm{m}$ placed such that its six faces are given by equations $x=0, x=+a, y=0, y=+a, z=0$ and $z=+a$, placed in electric field given by $\overrightarrow{E}=x^2\hat{\mathrm{i}}+y\hat{\mathrm{j}} \mathrm{N} {\mathrm{C}}^{-1}$. Find the electric flux crossing out of the cube in the unit of ${10}^{-4} \mathrm{N}{ \mathrm{m}}^2 {\mathrm{C}}^{-1}$.

A cylinder of radius $R$ and length $L$ is placed in a uniform electric field $E$ parallel to the cylinder axis. The total flux for the surface of the cylinder is given by

The black shapes in the figure below are closed surfaces. The electric field lines are in red. For which case, the net flux through the surfaces is non-zero?

A circular plate sheet of radius $10 \mathrm{cm}$ is placed in a uniform electric field of $2\sqrt{3}\times {10}^5 \mathrm{N} {\mathrm{C}}^{-1},$ making an angle of $60°$ with the field. Then find the electric flux through the sheet.

The $\mathrm{ }\mathrm{S}\mathrm{I}$ unit of electric flux is:

The $\mathrm{ }\mathrm{S}\mathrm{I}$ unit of electric flux is:

The net flux passing through the surface of an imaginary cube of edge length $\mathrm{a}$ placed in space having a uniform volume charge density, is $\mathrm{\varphi }$. The net flux passing through the surface of an imaginary sphere of radius $\mathrm{a}$ in the same space is

The electric field in a region is given by $\overrightarrow{E}=\left(\frac{3}{5}{E}_0\hat{\mathrm{i}}+\frac{4}{5}{E}_0\hat{\mathrm{j}}\right) \mathrm{N} {\mathrm{C}}^{-1}$ The ratio of flux of reported field through the rectangular surface of area $0.2 {\mathrm{m}}^2$ (parallel to $\mathrm{y}-\mathrm{z}$ plane) to that of the surface of area $0.3 {\mathrm{m}}^2($parallel to $\mathrm{x}-\mathrm{z}$ plane ) is $a:b,$ find $a$.

[Here $\hat{\mathrm{i}},\hat{\mathrm{j}}$ and $\hat{\mathrm{k}}$ are unit vectors along $\mathrm{x},\mathrm{y}$ and $\mathrm{z}$-axes respectively]

A positive point charge $Q$is placed (on the axis of the disc) at a distance of $4R$above the center of a disc of radius $R$as shown in situation $I.$The magnitude of electric flux through the disc is $\varphi .$Now, a hemispherical shell of a radius $R$is placed over the disc such that it forms a closed surface as shown in situation $\mathrm{II}.$The flux through the curved surface in the situation $\mathrm{II}$ taking direction of area vector along outward normal as positive is

In a region of space having a spherically symmetric distribution of charge, the electric flux enclosed by a concentric spherical Gaussian surface varies with a radius $r$ as 
$\mathrm{\varphi }=\left\{\begin{array}{ll}\frac{{\mathrm{\varphi }}_0{r}^2}{R^3},& r\le R\\ {\mathrm{\varphi }}_0,& r>R\end{array}\right.$ where $R$ and ${\mathrm{\varphi }}_0$ are the constants.

The electric field strength in the region is given as, 

Which one is the SI unit of electric flux

An unknown magnitude of charged particle is placed at some distance along the axis of a uniformly charged disc of surface charge density $\sigma$. The flux due to the charge particle through the disc is $\varphi$. The electric force exerted by the disc on the charged particle is